If M 11 = - 40 , M 12 = - 10 and M 13 = 35 of the determinant = | 1 3 - 2 4 - 5 6 3 5 2 | , then the value of is:

Question

If $M_{11} = - 40$ , $M_{12} = - 10$ and $M_{13} = 35$ of the determinant $Δ =$ $| \begin{matrix} 1 & 3 & - 2 \\ 4 & - 5 & 6 \\ 3 & 5 & 2 \end{matrix} |$ $,$ then the value of $Δ$ is:

Smart Achievers · Accepted Answer

(1)

Ans. $- 80$

Explanation:

$Δ = a_{11} A_{11} + a_{12} A_{12} + a_{13} A_{13}$

$= a_{11} M_{11} - a_{12} M_{12} + a_{13} M_{13}$

$= 1 (- 40) - 3 (- 10) + (- 2) (35)$

$= - 40 + 30 - 70$ $= - 80$

Solution

Q.
If $M_{11} = - 40$ , $M_{12} = - 10$ and $M_{13} = 35$ of the determinant $Δ =$ $| \begin{matrix} 1 & 3 & - 2 \\ 4 & - 5 & 6 \\ 3 & 5 & 2 \end{matrix} |$ $,$ then the value of $Δ$ is:

1 $- 80$

2 $60$

3 $70$

4 $100$

Ans.
(1)

Ans. $- 80$

Explanation:

$Δ = a_{11} A_{11} + a_{12} A_{12} + a_{13} A_{13}$

$= a_{11} M_{11} - a_{12} M_{12} + a_{13} M_{13}$

$= 1 (- 40) - 3 (- 10) + (- 2) (35)$

$= - 40 + 30 - 70$ $= - 80$

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Solution

Q. If M11=-40, M12=-10 and M13=35 of the determinant Δ=|13-24-56352|, then the value of Δ is:

1 -80

2 60

3 70

4 100

Ans. (1) Ans. -80 Explanation: Δ=a11A11+a12A12+a13A13 =a11M11-a12M12+a13M13 =1(-40)-3(-10)+(-2)(35) =-40+30-70=-80