If is the permittivity of free space and E is the electric field, then has the dimensions

Question

If $\in_{0}$ is the permittivity of free space and E is the electric field, then $\in_{0} E^{2}$ has the dimensions [2024]

Smart Achievers · Accepted Answer

(2)

Energy per unit volume = $\frac{1}{2} \in_{0} E^{2}$

$\frac{1}{2} \in_{0} E^{2} \Rightarrow [M L^{- 1} T^{- 2}] = \in_{0} E^{2}$

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