If F is force, V is velocity, H is latent heat, and s is specific heat

Question

If F is force, V is velocity, H is latent heat, and s is specific heat, then match the quantity given in Column I with the dimensions given in Column II.

	Column I		Column II
i.	F	a.	$L^{2} T^{- 2}$
ii.	V	b.	$L^{2} T^{- 2} K^{- 1}$
iii.	H	c.	$M L T^{- 2}$
iv.	S	d.	$L T^{- 1}$

Smart Achievers · Accepted Answer

(1)

$i i i .$ $[H] =$ $[\frac{H e a t}{M a s s}] = \frac{M L^{2} T^{- 2}}{M} = L^{2} T^{- 2}$

$i v .$ $[s] = [\frac{H e a t}{M a s s \times T e m p e r a t u r e}] = \frac{M L^{2} T^{- 2}}{M K} = L^{2} T^{- 2} K^{- 1}$

Solution

Q.
If F is force, V is velocity, H is latent heat, and s is specific heat, then match the quantity given in Column I with the dimensions given in Column II.

Column I Column II

i. F a. $L^{2} T^{- 2}$

ii. V b. $L^{2} T^{- 2} K^{- 1}$

iii. H c. $M L T^{- 2}$

iv. S d. $L T^{- 1}$

1 i → c, ii → d, iii → a, iv → b

2 i → a, ii → b, iii → c, iv → d

3 i → d, ii → a, iii → b, iv → c

4 i → c, ii → a, iii → b, iv → d

Ans.
(1)

$i i i .$ $[H] =$ $[\frac{H e a t}{M a s s}] = \frac{M L^{2} T^{- 2}}{M} = L^{2} T^{- 2}$

$i v .$ $[s] = [\frac{H e a t}{M a s s \times T e m p e r a t u r e}] = \frac{M L^{2} T^{- 2}}{M K} = L^{2} T^{- 2} K^{- 1}$

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