If end points of a diameter of a circle are (-5,4)and (1,0), then the radius

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Solution

Q.
If end points of a diameter of a circle are $(- 5, 4) a n d (1, 0),$ then the radius of the circle is:

1 $2 \sqrt{13} u n i t s$

2 $\sqrt{13} u n i t s$

3 $4 \sqrt{2} u n i t s$

4 $2 \sqrt{2} u n i t s$

Ans.
(2)

Let given end points of diameter be A(-5,4) and B(1,0).

∴ Diameter has length,

$A B = \sqrt{(1 + 5)^{2} + (0 - 4)^{2}} = \sqrt{36 + 16} = \sqrt{52} = 2 \sqrt{13} units Radiusofcircle = \frac{2 \sqrt{13}}{2} = \sqrt{13} units .$

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