If Earth has a mass nine times and radius twice to that of a planet P. Then will be the minimum velocity required by a rocket to pull out of gravitational force of P, where is escape velocity on Earth. The value of is [2023]

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
If Earth has a mass nine times and radius twice to that of a planet P. Then $\frac{v_{e}}{3} \sqrt{x} {ms}^{- 1}$ will be the minimum velocity required by a rocket to pull out of gravitational force of P, where $v_{e}$ is escape velocity on Earth. The value of $x$ is [2023]

1 2

2 3

3 18

4 1

Ans.
(1)

$v_{(escape)planet} = \sqrt{\frac{2 G M_{p}}{R_{p}}}$

$= \sqrt{\frac{2 G (\frac{M_{e}}{9})}{(\frac{R_{e}}{2})}} = \frac{v_{e} \sqrt{2}}{3}$

$∴$ $x = 2$

Want Us to Email you About Special Offers & Updates?