If cos(sin-125+cos-1x)=0, then x is equal to:
(2)
Ans. 25
Explanation:
We have,
cos(sin-125+cos-1x)=0
⇒ sin-125+cos-1x=cos-10
⇒ sin-125+cos-1x=π2
⇒ cos-1x=π2-sin-125
⇒ cos-1x=cos-125 (∵ cos-1x+sin-1x=π2)
∴ x=25