If coefficient of x2y3z4 in (x+y+z)n is A, (where A≠0, n∈ℕ) then coefficient of x4y4z is
(3)
Since x2y3z4 is occurring in the expansion of (x+y+z)n, so n should be 9 only.
Now A=9!2!×3!×4!=1260
Coefficient of x4y4z=9!4!×4!=630=A2