If C3:C3=10:1,n2n then the ratio (n2+3n):(n2-3n+4) is [2023]
(3)
We have, C32n:nC3=10:1
⇒(2n!(2n-3)!3!)n!3!(n-3)!=101
⇒2n(2n-1)(2n-2)6×6n(n-1)(n-2)=101
⇒4(2n-1)(n-2)=10 ⇒8n-4=10n-20 ⇒16=2n⇒n=8 ∴ (n2+3n):(n2-3n+4)=(64+24):(64-24+4) = 88:44=2:1