If α and β are the zeros of a polynomial f(x)=px2–2x+3p and α + β = αβ, then p is
(2)
Given, f(x)=px2-2x+3p
Since α and β are the zeroes of the given polynomial.
∴ α+β=-(-2)p=2p, and αβ=3pp=3
∵ α+β=αβ (given)
∴ 2p=3⇒p=23