If α and β(α<β) are the roots of the equation x2+bx+c=0, where c<0<b, then [2000]
(2)
Given : c<0<b and α+β=-b ⋯(i)
αβ=c ⋯(ii)
From (ii), c<0⇒αβ<0⇒Either α is negative or β is negative and second quantity is positive.
From (i), b>0⇒-b<0⇒α+β<0
⇒the sum is negative
⇒(Modulus of negative quantity)>(Modulus of positive quantity)
But given α<β. Therefore, it is clear that α is negative and β is positive
and modulus of α is greater than modulus of β
⇒α<0<β<|α|