If all the six digit numbers x1 x2 x3 x4 x5 x6 with 0<x1<x2<x3<x4<x5<x6 are arranged in the increasing order, then the sum of the digits in the 72th number is ___________ . [2023]
(32)
2 4 5 6 7 8 → 72th word. So, 2 + 4 + 5 + 6 + 7 + 8 = 32