If a person observes the ship whose angle of depression changes from 60° to 30° then how far be ship from the building if the observer is at 20 m of height (including him)?

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Solution

Q.
A person/observer on the sea coast observes two ships in the sea, both the ships are in same straight path one behind the other.

If the observer is on his building of height 20 meters (including observer) and he observes the angle of depression of two ships as 45° and 60° respectively.

On the basis of above information answer the following questions.

Q. If a person observes the ship whose angle of depression changes from 60° to 30° then how far be ship from the building if the observer is at 20 m of height (including him)

Ans.
(34.6)

$\tan 30 ° = \frac{O B}{O A} \Rightarrow \frac{1}{\sqrt{3}} = \frac{20}{O A} \Rightarrow O A = 20 \sqrt{3} m = 34.6 m$

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