If a person observes a ship whose angle of depression is 60° then how much distance is the ship away from the building?

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Solution

Q.
A person/observer on the sea coast observes two ships in the sea, both the ships are in same straight path one behind the other.

If the observer is on his building of height 20 meters (including observer) and he observes the angle of depression of two ships as 45° and 60° respectively.

On the basis of above information answer the following questions.

Q. If a person observes a ship whose angle of depression is 60° then how much distance is the ship away from the building

Ans.
(11.55)

$\tan 60 ° = \frac{O C}{A C} \Rightarrow \sqrt{3} = \frac{20}{A C} \Rightarrow A C = \frac{20}{\sqrt{3}} = \frac{20 \sqrt{3}}{3} m = 11.55 m$

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