If A = [2 2 9 4] and I = [1 0 0 1] then 20 A - 1 =

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Solution

Q.
If $A = [\begin{matrix} 2 & 2 \\ 9 & 4 \end{matrix}]$ and $I = [\begin{matrix} 1 & 0 \\ 0 & 1 \end{matrix}]$ then $20 A^{- 1}$ = ____

1 $2 A - 12 I$

2 $A - 6 I$

3 $A + 6 I$

4 $2 A + 12 I$

Ans.
(1)

$A^{- 1} = \frac{1}{8 - 18} [\begin{matrix} 4 & - 2 \\ - 9 & 2 \end{matrix}],$ $10 A^{- 1} = [\begin{matrix} - 4 & 2 \\ 9 & - 2 \end{matrix}]$

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