Q.

If 15sin4α+10cos4α=6, for α∈R, then the value of 27sec6α+8cosec6α is equal to:

1 350  
2 250  
3 400  
4 500  

Ans.

(2)

15sin4α+10(1-sin2α)2=6.25sin4α-20sin2α+4=0

⇒25sin4α-10sin2α-10sin2α+4=0

⇒(5sin2α-2)=0

⇒sin2α=25