If 15sin4α+10cos4α=6, for α∈R, then the value of 27sec6α+8cosec6α is equal to:
(2)
15sin4α+10(1-sin2α)2=6.25sin4α-20sin2α+4=0
⇒25sin4α-10sin2α-10sin2α+4=0
⇒(5sin2α-2)=0
⇒sin2α=25