Identify the metal ions among having a spin-only magnetic moment value more than 3.0 BM. The sum of unpaired electrons present in the high spin octahedral complexes form

Question

Identify the metal ions among ${Co}^{2 +}, {Ni}^{2 +}, {Fe}^{2 +}, V^{3 +} and {Ti}^{2 +}$ having a spin-only magnetic moment value more than 3.0 BM. The sum of unpaired electrons present in the high spin octahedral complexes formed by those metal ions is____________. [2026]

Smart Achievers · Accepted Answer

(7)

$V^{3 +} = {(Ar)}_{18} 3 d^{2}$

${Ti}^{2 +} = {(Ar)}_{18} 3 d^{2}$

${Ni}^{2 +} = {(Ar)}_{18} 3 d^{8}$

${Fe}^{2 +} = {(Ar)}_{18} 3 d^{6}$

${Co}^{2 +} = {(Ar)}_{18} 3 d^{7}$

${Only for Fe}^{2 +} {and Co}^{2 +}, μ is more than 3.0 B.M.$

$∴$ Number of unpaired electrons = 4 + 3 = 7

Solution

Q.
Identify the metal ions among ${Co}^{2 +}, {Ni}^{2 +}, {Fe}^{2 +}, V^{3 +} and {Ti}^{2 +}$ having a spin-only magnetic moment value more than 3.0 BM. The sum of unpaired electrons present in the high spin octahedral complexes formed by those metal ions is____________. [2026]

Ans.
(7)

$V^{3 +} = {(Ar)}_{18} 3 d^{2}$

${Ti}^{2 +} = {(Ar)}_{18} 3 d^{2}$

${Ni}^{2 +} = {(Ar)}_{18} 3 d^{8}$

${Fe}^{2 +} = {(Ar)}_{18} 3 d^{6}$

${Co}^{2 +} = {(Ar)}_{18} 3 d^{7}$

${Only for Fe}^{2 +} {and Co}^{2 +}, μ is more than 3.0 B.M.$

$∴$ Number of unpaired electrons = 4 + 3 = 7

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Solution

Q. Identify the metal ions among Co2+, Ni2+, Fe2+, V3+ and Ti2+ having a spin-only magnetic moment value more than 3.0 BM. The sum of unpaired electrons present in the high spin octahedral complexes formed by those metal ions is____________. [2026]

Ans. (7) V3+=(Ar)18 3d2 Ti2+=(Ar)18 3d2 Ni2+=(Ar)18 3d8 Fe2+=(Ar)18 3d6 Co2+=(Ar)18 3d7 Only for Fe2+ and Co2+, μ is more than 3.0 B.M. ∴ Number of unpaired electrons = 4 + 3 = 7

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Q.
Identify the metal ions among ${Co}^{2 +}, {Ni}^{2 +}, {Fe}^{2 +}, V^{3 +} and {Ti}^{2 +}$ having a spin-only magnetic moment value more than 3.0 BM. The sum of unpaired electrons present in the high spin octahedral complexes formed by those metal ions is____________. [2026]

Ans.
(7)

$V^{3 +} = {(Ar)}_{18} 3 d^{2}$

${Ti}^{2 +} = {(Ar)}_{18} 3 d^{2}$

${Ni}^{2 +} = {(Ar)}_{18} 3 d^{8}$

${Fe}^{2 +} = {(Ar)}_{18} 3 d^{6}$

${Co}^{2 +} = {(Ar)}_{18} 3 d^{7}$

${Only for Fe}^{2 +} {and Co}^{2 +}, μ is more than 3.0 B.M.$

$∴$ Number of unpaired electrons = 4 + 3 = 7