How many digits will be there after decimal point in 12th term of the sequence: 32, 16, 8, 4, ..... ?

Question

Smart Achievers · Accepted Answer

(2)

$We have, 32, 16, 8, 4, \dots are in G.P.$

$a = 32, r = \frac{1}{2}$

Then, $12^{th}$ term of the sequence $= a r^{12 - 1}$

$= 32 \times \frac{1}{2^{11}} = 2^{5} \times 2^{- 11} = 2^{- 6} = 0.015625$

Hence, six digits will be there after decimal point in $12^{th}$ term of the sequence.

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