Given the value of Rydberg constant is , the wave number of the last line of the Balmer series in hydrogen spectrum will be [2016]

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

Q.
Given the value of Rydberg constant is $10^{7}$ $m^{- 1}$ , the wave number of the last line of the Balmer series in hydrogen spectrum will be [2016]

1 $0.25 \times 10^{7}$ $m^{- 1}$

2 $2.5 \times 10^{7}$ $m^{- 1}$

3 $0.025 \times 10^{4}$ $m^{- 1}$

4 $0.5 \times 10^{7}$ $m^{- 1}$

Ans.
(1)

Here, $R = 10^{7}$ $m^{- 1}$

The wave number of the last line of the Balmer series in hydrogen spectrum is given by

$\frac{1}{λ} = R (\frac{1}{2^{2}} - \frac{1}{\infty^{2}}) = \frac{R}{4} = \frac{10^{7}}{4} = 0.25 \times 10^{7}$ $m^{- 1}$

Solution

Q.
Given the value of Rydberg constant is $10^{7}$ $m^{- 1}$ , the wave number of the last line of the Balmer series in hydrogen spectrum will be [2016]

1 $0.25 \times 10^{7}$ $m^{- 1}$

2 $2.5 \times 10^{7}$ $m^{- 1}$

3 $0.025 \times 10^{4}$ $m^{- 1}$

4 $0.5 \times 10^{7}$ $m^{- 1}$

Ans.
(1)

Here, $R = 10^{7}$ $m^{- 1}$

The wave number of the last line of the Balmer series in hydrogen spectrum is given by

$\frac{1}{λ} = R (\frac{1}{2^{2}} - \frac{1}{\infty^{2}}) = \frac{R}{4} = \frac{10^{7}}{4} = 0.25 \times 10^{7}$ $m^{- 1}$

Want Us to Email you About Special Offers & Updates?

Solution

Q. Given the value of Rydberg constant is 107 m-1, the wave number of the last line of the Balmer series in hydrogen spectrum will be [2016]

1 0.25×107 m-1

2 2.5×107 m-1

3 0.025×104 m-1

4 0.5×107 m-1

Ans. (1) Here, R=107 m-1 The wave number of the last line of the Balmer series in hydrogen spectrum is given by 1λ=R(122-1∞2)=R4=1074=0.25×107 m-1

Want Us to Email you About Special Offers & Updates?

Q.
Given the value of Rydberg constant is $10^{7}$ $m^{- 1}$ , the wave number of the last line of the Balmer series in hydrogen spectrum will be [2016]

1 $0.25 \times 10^{7}$ $m^{- 1}$

2 $2.5 \times 10^{7}$ $m^{- 1}$

3 $0.025 \times 10^{4}$ $m^{- 1}$

4 $0.5 \times 10^{7}$ $m^{- 1}$

Ans.
(1)

Here, $R = 10^{7}$ $m^{- 1}$

The wave number of the last line of the Balmer series in hydrogen spectrum is given by

$\frac{1}{λ} = R (\frac{1}{2^{2}} - \frac{1}{\infty^{2}}) = \frac{R}{4} = \frac{10^{7}}{4} = 0.25 \times 10^{7}$ $m^{- 1}$