From the given statements, incorrect statements are:

I. H.O.M.O. of dioxygen is $π^{*} 2 p$ [H.O.M.O. = highest occupied molecular orbital]

II. L.U.M.O. of dinitrogen is $π 2 p$ [L.U.M.O. = lowest unoccupied molecular orbital]

III. Bond strength of $B_{2} > F_{2}$

Question

From the given statements, incorrect statements are:

I. H.O.M.O. of dioxygen is $π^{*} 2 p$ [H.O.M.O. = highest occupied molecular orbital]

II. L.U.M.O. of dinitrogen is $π 2 p$ [L.U.M.O. = lowest unoccupied molecular orbital]

III. Bond strength of $B_{2} > F_{2}$

Smart Achievers · Accepted Answer

(2)

$π^{*} 2 p$

$Bond strength of B_{2} > F_{2} . Lower bond strength of F_{2} is due to repulsion between lone pairs of the bonded F atoms.$

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