From Ampere’s circuital law for a long straight wire of circular cross-section carrying a steady current, the variation of magnetic field in the inside and outside region of the wire is [2022]

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Q.
From Ampere’s circuital law for a long straight wire of circular cross-section carrying a steady current, the variation of magnetic field in the inside and outside region of the wire is [2022]

1 uniform and remains constant for both the regions

2 a linearly increasing function of distance up to the boundary of the wire and then linearly decreasing for the outside region

3 a linearly increasing function of distance $r$ up to the boundary of the wire and then decreasing one with $1 / r$ dependence for the outside region

4 a linearly decreasing function of distance up to the boundary of the wire and then a linearly increasing one for the outside region

Ans.
(3)

Using Ampere’s circuital law

$B_{in} = \frac{μ_{0} I r}{2 π a^{2}}, or B_{in} \propto r$

$B_{out} = \frac{μ_{0} I}{2 π r}, or B_{out} \propto \frac{1}{r}$

Solution

Q.
From Ampere’s circuital law for a long straight wire of circular cross-section carrying a steady current, the variation of magnetic field in the inside and outside region of the wire is [2022]

1 uniform and remains constant for both the regions

2 a linearly increasing function of distance up to the boundary of the wire and then linearly decreasing for the outside region

3 a linearly increasing function of distance $r$ up to the boundary of the wire and then decreasing one with $1 / r$ dependence for the outside region

4 a linearly decreasing function of distance up to the boundary of the wire and then a linearly increasing one for the outside region

Ans.
(3)

Using Ampere’s circuital law

$B_{in} = \frac{μ_{0} I r}{2 π a^{2}}, or B_{in} \propto r$

$B_{out} = \frac{μ_{0} I}{2 π r}, or B_{out} \propto \frac{1}{r}$

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Solution

Q. From Ampere’s circuital law for a long straight wire of circular cross-section carrying a steady current, the variation of magnetic field in the inside and outside region of the wire is [2022]

1 uniform and remains constant for both the regions

2 a linearly increasing function of distance up to the boundary of the wire and then linearly decreasing for the outside region

3 a linearly increasing function of distance r up to the boundary of the wire and then decreasing one with 1/r dependence for the outside region

4 a linearly decreasing function of distance up to the boundary of the wire and then a linearly increasing one for the outside region

Ans. (3) Using Ampere’s circuital law Bin=μ0Ir2πa2, or Bin∝r Bout=μ0I2πr, or Bout∝1r

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Q.
From Ampere’s circuital law for a long straight wire of circular cross-section carrying a steady current, the variation of magnetic field in the inside and outside region of the wire is [2022]

3 a linearly increasing function of distance $r$ up to the boundary of the wire and then decreasing one with $1 / r$ dependence for the outside region

Ans.
(3)

Using Ampere’s circuital law

$B_{in} = \frac{μ_{0} I r}{2 π a^{2}}, or B_{in} \propto r$

$B_{out} = \frac{μ_{0} I}{2 π r}, or B_{out} \propto \frac{1}{r}$