From a lot containing 10 defective and 90 non-defective bulbs, 8 bulbs are selected one by one with replacement. Then the probability of getting at least 7 defective bulbs is [2026]

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Solution

Q.
From a lot containing 10 defective and 90 non-defective bulbs, 8 bulbs are selected one by one with replacement. Then the probability of getting at least 7 defective bulbs is [2026]

1 $\frac{73}{10^{8}}$

2 $\frac{67}{10^{8}}$

3 $\frac{81}{10^{8}}$

4 $\frac{7}{10^{7}}$

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