For x∈(0,π), the equation sinx+2sin 2x-sin 3x=3 has [2014]
(4)
sinx+2sin 2x-sin 3x=3
⇒sinx+4sinxcosx-3sinx+4sin3x=3
⇒sinx(-2+4cosx+4sin2x)=3
⇒sinx(-2+4cosx+4-4cos2x)=3
2+4cosx-4cos2x=3sinx [∵0≤sinx≤1]
⇒2-4(cos2x-2cosx·12+14)+1=3sinx
⇒3-4(cosx-12)2=3sinx ∴ L.H.S≤3 and R.H.S≥3
Hence, the equation has no solution.