Q.

For x∈(0,π), the equation sinx+2sin 2x-sin 3x=3 has                 [2014]

1 infinitely many solutions  
2 three solutions  
3 one solution  
4 no solution  

Ans.

(4)

sinx+2sin 2x-sin 3x=3

⇒sinx+4sinxcosx-3sinx+4sin3x=3

⇒sinx(-2+4cosx+4sin2x)=3

⇒sinx(-2+4cosx+4-4cos2x)=3

2+4cosx-4cos2x=3sinx   [∵0≤sinx≤1]

⇒2-4(cos2x-2cosx·12+14)+1=3sinx

⇒3-4(cosx-12)2=3sinx    ∴ L.H.S≤3 and R.H.S≥3

Hence, the equation has no solution.