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Solution


Q.

For very high frequencies, the effective impedance of the circuit (shown in the figure) will be                    [2023]


 
1 4 Ω  
2 6 Ω  
3 1 Ω  
4 3 Ω  

Ans.

(4)

As frequency is very high. Here, reactance due to capacitance varies inversely whereas reactance due to inductor varies directly.

Then, XC≈0

XL→∞

Effective circuit will be

Thus, capacitor acts as a short circuit while inductor as an open circuit. Effective impedance will be 1Ω+2Ω=3Ω