For the plane electromagnetic wave given by the ratio of average electric energy density to average magnetic energy density is [2023]

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Solution

Q.
For the plane electromagnetic wave given by $E = E_{0} \sin (ω t - k x) and B = B_{0} \sin (ω t - k x),$ the ratio of average electric energy density to average magnetic energy density is [2023]

1 1

2 2

3 4

4 1/2

Ans.
(1)

$\frac{Electric energy density}{Magnetic energy density} = \frac{\frac{1}{2} ε_{0} E_{rms}^{2}}{(\frac{B_{rms}^{2}}{2 μ_{0}})}$
$= {(\frac{E_{rms}}{B_{rms}})}^{2} \cdot μ_{0} ε_{0} [c = \frac{1}{μ_{0} ε_{0}}]$

$= \frac{c^{2}}{c^{2}} = 1$

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