Q.

For some data x1,x2,…,xn with respective frequencies f1,f2,…,fn,the value of ∑i=1nfi(xi-x) is equal to:

1 nx  
2 1  
3 ∑fi  
4 0  

Ans.

(4)

∑i=1nfi(xi-x)=f1(x1-x)+f2(x2-x)+⋯+fn(xn-x)=(f1x1+f2x2+…+fnxn)-(f1x+f2x+⋯+fnx)=∑i=1nfixi-xi=1nfi=∑i=1nfixi-∑i=1nfixi∑i=1nfi·∑i=1nfi=0x=∑i=1nfixi∑i=1nfi