For photo-electric effect with incident photon wavelength , the stopping potential is . Identify the correct variation(s) of with and . [2015]

Question

For photo-electric effect with incident photon wavelength $λ$ , the stopping potential is $V_{0}$ . Identify the correct variation(s) of $V_{0}$ with $λ$ and $\frac{1}{λ}$ . [2015]

Smart Achievers · Accepted Answer

(1, 3)

We know that

$\frac{h c}{λ} - ϕ = e V_{0} \Rightarrow \frac{h c}{e λ} - \frac{ϕ}{e} = V_{0} \Rightarrow \frac{h c}{e} (\frac{1}{λ}) - \frac{ϕ}{e} = V_{0}$

Therefore, $V_{0}$ versus $\frac{1}{λ}$ graph is a straight line with negative slope $(\frac{h c}{e})$ and positive intercept $(\frac{ϕ}{e}) .$

For $V_{0}$ versus $λ$ , we will get a hyperbola. As $λ$ decreases, $V_{0}$ increases. And $V_{0}$ becomes zero when $(\frac{h c}{λ}) = ϕ$ i.e., when $λ = λ_{0}$

Solution

Q.
For photo-electric effect with incident photon wavelength $λ$ , the stopping potential is $V_{0}$ . Identify the correct variation(s) of $V_{0}$ with $λ$ and $\frac{1}{λ}$ . [2015]

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Solution

Q. For photo-electric effect with incident photon wavelength λ, the stopping potential is V0. Identify the correct variation(s) of V0 with λ and 1λ. [2015]

1

2

3

4

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Q.
For photo-electric effect with incident photon wavelength $λ$ , the stopping potential is $V_{0}$ . Identify the correct variation(s) of $V_{0}$ with $λ$ and $\frac{1}{λ}$ . [2015]