For particle P revolving round the centre with radius of circular path and angular velocity , as shown in below figure, the projection of OP on the -axis at time is [2023]

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Solution

Q.
For particle P revolving round the centre $O$ with radius of circular path $r$ and angular velocity $ω$ , as shown in below figure, the projection of OP on the $x$ -axis at time $t$ is [2023]

Solution

Q.
For particle P revolving round the centre $O$ with radius of circular path $r$ and angular velocity $ω$ , as shown in below figure, the projection of OP on the $x$ -axis at time $t$ is [2023]

1 $x (t) = r \cos (ω t + \frac{π}{6})$

2 $x (t) = r \sin (ω t + \frac{π}{6})$

3 $x (t) = r \cos (ω t)$

4 $x (t) = r \cos (ω t - \frac{π}{6} ω)$

Ans.
(1)

$x (t) = r \cos (ω t + 30 °)$

$x (t) = r \cos (ω t + \frac{π}{6})$

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Solution

Q. For particle P revolving round the centre O with radius of circular path r and angular velocity ω, as shown in below figure, the projection of OP on the x-axis at time t is [2023]

1 x(t)=rcos(ωt+π6)

2 x(t)=rsin(ωt+π6)

3 x(t)=rcos(ωt)

4 x(t)=rcos(ωt-π6ω)

Ans. (1) x(t)=rcos(ωt+30°) x(t)=rcos(ωt+π6)

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Q.
For particle P revolving round the centre $O$ with radius of circular path $r$ and angular velocity $ω$ , as shown in below figure, the projection of OP on the $x$ -axis at time $t$ is [2023]

1 $x (t) = r \cos (ω t + \frac{π}{6})$

2 $x (t) = r \sin (ω t + \frac{π}{6})$

3 $x (t) = r \cos (ω t)$

4 $x (t) = r \cos (ω t - \frac{π}{6} ω)$

Ans.
(1)

$x (t) = r \cos (ω t + 30 °)$

$x (t) = r \cos (ω t + \frac{π}{6})$