Q.

For hyperbola x2cos2α-y2sin2α=1, which of the following remains constant with change in 'α'                    [2003]

1 abscissae of vertices  
2 abscissae of foci  
3 eccentricity  
4 directrix  

Ans.

(2)

Given equation of hyperbola is

x2cos2α-y2sin2α=1a=cosα, b=sinα

e=1+b2a2=1+tan2α=secα

ae=cosα·secα=1       Foci (±1,0)

Hence, foci remain constant with respect to α.