For hyperbola x2cos2α-y2sin2α=1, which of the following remains constant with change in 'α' [2003]
(2)
Given equation of hyperbola is
x2cos2α-y2sin2α=1⇒a=cosα, b=sinα
⇒e=1+b2a2=1+tan2α=secα
⇒ae=cosα·secα=1 ∴ Foci (±1,0)
Hence, foci remain constant with respect to α.