For conversion of compound A B , the rate constant of the reaction was found to be 4 . 6 × 10 - 5 L mol - 1 s - 1 . The order of the reaction is _______. [2023]

Question

For conversion of compound $A \to B$ , the rate constant of the reaction was found to be $4.6 \times 10^{- 5}$ L ${mol}^{- 1} s^{- 1}$ . The order of the reaction is _______. [2023]

Smart Achievers · Accepted Answer

(2)

For $n^{th}$ order reaction

Units of $k = \frac{Rate}{{(conc)}^{n}} = {mol}^{1 - n} L^{n - 1} s^{- 1}$

For a given reaction, unit of $k = {mol}^{- 1} {L sec}^{- 1}$

$∴$ $Order of the reaction (n) = 2$

Solution

Q.
For conversion of compound $A \to B$ , the rate constant of the reaction was found to be $4.6 \times 10^{- 5}$ L ${mol}^{- 1} s^{- 1}$ . The order of the reaction is _______. [2023]

Ans.
(2)

For $n^{th}$ order reaction

Units of $k = \frac{Rate}{{(conc)}^{n}} = {mol}^{1 - n} L^{n - 1} s^{- 1}$

For a given reaction, unit of $k = {mol}^{- 1} {L sec}^{- 1}$

$∴$ $Order of the reaction (n) = 2$

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Solution

Q. For conversion of compound A→B, the rate constant of the reaction was found to be 4.6×10-5 L mol-1s-1. The order of the reaction is _______. [2023]

Ans. (2) For nth order reaction Units of k=Rate(conc)n=mol1-n Ln-1 s-1 For a given reaction, unit of k=mol-1 L sec-1 ∴ Order of the reaction (n)=2

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Q.
For conversion of compound $A \to B$ , the rate constant of the reaction was found to be $4.6 \times 10^{- 5}$ L ${mol}^{- 1} s^{- 1}$ . The order of the reaction is _______. [2023]

Ans.
(2)

For $n^{th}$ order reaction

Units of $k = \frac{Rate}{{(conc)}^{n}} = {mol}^{1 - n} L^{n - 1} s^{- 1}$

For a given reaction, unit of $k = {mol}^{- 1} {L sec}^{- 1}$

$∴$ $Order of the reaction (n) = 2$