For any positive integer n, let Sn:(0,∞)→ℝ be defined by Sn(x)=∑k=1ncot-1(1+k(k+1)x2x), where for any x∈ℝ, cot-1x∈(0,π) and tan-1(x)∈(-π2,π2). Then which of the following statements is (are) TRUE [2021]
(1, 2)
Given that Sn(x)=∑k=1ncot-1(1+k(k+1)x2x)
=∑k=1ntan-1(x1+kx(kx+x))
=∑k=1ntan-1((kx+x)-(kx)1+(kx+x)(kx))
⇒ Sn(x)=tan-1(nx+x)-tan-1x=tan-1(nx1+(n+1)x2)
(1) S10(x)=tan-1(10x1+11x2)=π2-tan-1(1+11x210x), (x>0)
Option (1) is correct
(2) limn→∞cot(Sn(x))=limn→∞cot[cot-1(1+(n+1)x2nx)]
=limn→∞1n+(1+1n)x2x=x, (x>0)
Option (2) is correct
(3) S3(x)=tan-1(3x1+4x2)=π4
⇒ 4x2-3x+1=0⇒x∉ℝ [∵ D is negative]
Option (3) is incorrect
(4) For x=1,
tan(Sn(x))=nn+2≥12, for n≥3
Option (4) is incorrect