Q.

For all 'x', x2+2ax+10-3a>0, then the interval in which 'a' lies is                   [2004]

1 a<-5  
2 -5<a<2  
3 a>5  
4 2<a<5  

Ans.

(2)

f(x)=ax2+bx+c has same sign as that of a if D<0.

Since x2+2ax+10-3a>0 x

 D<04a2-4(10-3a)<0

a2+3a-10<0

(a+5)(a-2)<0a(-5,2)