For a simple pendulum, a graph is plotted between its kinetic energy (KE) and potential energy (PE)

Question

For a simple pendulum, a graph is plotted between its kinetic energy (KE) and potential energy (PE) against its displacement d. Which one of the following represents these correctly? (graphs are schematic and not drawn to scale)

Smart Achievers · Accepted Answer

(4)

$K . E = \frac{1}{2} k (A^{2} - d^{2})$ and $P . E = \frac{1}{2} k d^{2}$

At mean position $d = 0$ . At extreme position $d = A$ .

Solution

Q.
For a simple pendulum, a graph is plotted between its kinetic energy (KE) and potential energy (PE) against its displacement d. Which one of the following represents these correctly (graphs are schematic and not drawn to scale)

1

2

3

4

Ans.
(4)

$K . E = \frac{1}{2} k (A^{2} - d^{2})$ and $P . E = \frac{1}{2} k d^{2}$

At mean position $d = 0$ . At extreme position $d = A$ .

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Solution

Q. For a simple pendulum, a graph is plotted between its kinetic energy (KE) and potential energy (PE) against its displacement d. Which one of the following represents these correctly (graphs are schematic and not drawn to scale)

1

2

3

4

Ans. (4) K.E=12k(A2-d2) and P.E=12kd2 At mean position d=0. At extreme position d=A.

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Q.
For a simple pendulum, a graph is plotted between its kinetic energy (KE) and potential energy (PE) against its displacement d. Which one of the following represents these correctly (graphs are schematic and not drawn to scale)

Ans.
(4)

$K . E = \frac{1}{2} k (A^{2} - d^{2})$ and $P . E = \frac{1}{2} k d^{2}$

At mean position $d = 0$ . At extreme position $d = A$ .