Five positive charges each having charge q are placed at the vertices of a pentagon as shown in the figure.The electric potential (V) and the electric field $(\vec{E})$ at the center O of the pentagon due to these five positive charges are: [2026]

Question

Smart Achievers · Accepted Answer

(2)

$Electric potential \Rightarrow V = \frac{5 k q}{R}$

$As regular polygon \Rightarrow \vec{E} = 0$

Solution

Q.
Five positive charges each having charge q are placed at the vertices of a pentagon as shown in the figure.The electric potential (V) and the electric field $(\vec{E})$ at the center O of the pentagon due to these five positive charges are: [2026]

1 $V = \frac{5 q}{4 π ε_{0} r} and \vec{E} = \frac{5 q}{4 π ε_{0} r^{2}} \hat{r}$

2 $V = \frac{5 q}{4 π ε_{0} r} and \vec{E} = 0$

3 $V = 0 and \vec{E} = 0$

4 $V = \frac{5 q}{4 π ε_{0} r} and \vec{E} = \frac{5 \sqrt{3} q}{8 π ε_{0} r^{2}} \hat{r}$

Ans.
(2)

$Electric potential \Rightarrow V = \frac{5 k q}{R}$

$As regular polygon \Rightarrow \vec{E} = 0$

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Solution

Q. Five positive charges each having charge q are placed at the vertices of a pentagon as shown in the figure.The electric potential (V) and the electric field (E→) at the center O of the pentagon due to these five positive charges are: [2026]

1 V=5q4πε0r and E→=5q4πε0r2r^

2 V=5q4πε0r and E→=0

3 V=0 and E→=0

4 V=5q4πε0r and E→=53 q8πε0r2r^

Ans. (2) Electric potential ⇒V=5kqR As regular polygon ⇒E→=0