Find the probability that the school chosen at random has 10 or less than 10 computers.

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Q.
Computer-based learning (CBL) refers to any teaching methodology that makes use of computers for information transmission. At an elementary school level, computer applications can be used to display multimedia lesson plans. A survey was done on 1000 elementary and secondary schools of Assam and they were classified by the number of computers they had.

Number of Computers

1–10

11–20

21–50

51–100

101 and more

Number of Schools

250

200

290

180

80

Based on the above information, answer the following questions:

One school is chosen at random. Then:

(iii) Find the probability that the school chosen at random has 10 or less than 10 computers.

Number of Computers	1–10	11–20	21–50	51–100	101 and more
Number of Schools	250	200	290	180	80

1 1/4

2 1/2

3 1/3

4 1/5

Ans.
(1)

Let H be the event that the school chosen at random has 10 or less than 10 computers i.e.,
n(H)=250

$P (H) = \frac{n (H)}{n (S)} = \frac{250}{1000} = \frac{1}{4}$ .

Solution

1 1/4

2 1/2

3 1/3

4 1/5

Ans.
(1)

Let H be the event that the school chosen at random has 10 or less than 10 computers i.e.,
n(H)=250

$P (H) = \frac{n (H)}{n (S)} = \frac{250}{1000} = \frac{1}{4}$ .

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Solution

1 1/4

2 1/2

3 1/3

4 1/5

Ans. (1) Let H be the event that the school chosen at random has 10 or less than 10 computers i.e., n(H)=250 P(H)=n(H)n(S)=2501000=14.

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Ans.
(1)

Let H be the event that the school chosen at random has 10 or less than 10 computers i.e.,
n(H)=250

$P (H) = \frac{n (H)}{n (S)} = \frac{250}{1000} = \frac{1}{4}$ .