Figure represents the extension of a wire of length 1 meter, suspended from the ceiling of the room at one end with load W

Question

Figure represents the extension $(Δ l)$ of a wire of length 1 meter, suspended from the ceiling of the room at one end with load W connected to the other end. If the cross-sectional area of the wire is $10^{- 5} m^{2}$ then the Young's modulus of the wire is ______ $N / m^{2}$ . [2026]

Smart Achievers · Accepted Answer

(3)

$\frac{Δ l}{W} = \tan θ = \frac{Δ y}{Δ x} = \frac{1 \times 10^{- 4}}{10} = 10^{- 5}$

$\Rightarrow \frac{W}{Δ l} = 10^{5}$

$\Rightarrow Y = \frac{F / A}{Δ l / l} = \frac{F l}{A Δ l} = (\frac{W}{Δ l}) \frac{l}{A}$

$\Rightarrow Y = \frac{10^{5} \times 1}{10^{- 5}} = 10^{10} {N/m}^{2}$

Solution

Q.
Figure represents the extension $(Δ l)$ of a wire of length 1 meter, suspended from the ceiling of the room at one end with load W connected to the other end. If the cross-sectional area of the wire is $10^{- 5} m^{2}$ then the Young's modulus of the wire is ______ $N / m^{2}$ . [2026]

1 $1.0 \times 10^{11}$

2 $2.0 \times 10^{10}$

3 $1.0 \times 10^{10}$

4 $2.0 \times 10^{11}$

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Solution

Q. Figure represents the extension (Δl) of a wire of length 1 meter, suspended from the ceiling of the room at one end with load W connected to the other end. If the cross-sectional area of the wire is 10-5 m2 then the Young's modulus of the wire is ______ N/m2. [2026]

1 1.0×1011

2 2.0×1010

3 1.0×1010

4 2.0×1011