Figure 1 shows the configuration of main scale and Vernier scale before measurement. Fig. 2 shows the configuration corresponding to the measurement of diameter D of a tube. The measured value of D is : [2025]

Question

Smart Achievers · Accepted Answer

(3)

From figure 1

$10 MSD = 1 cm, so 1 MSD = 0.1 cm$

$7 MSD = 10 VSD$

$∴ 1 VSD = 0.07 cm$

$Least count (L.C.) = 1 MSD - 1 VSD = 0.1 - 0.07 = 0.03 cm$

Vernier scale 1 marking matches with main scale division

$Measurement of diameter, D = MSR + VSR \times L.C.$

$= 0.1 + 1 \times 0.03 = 0.13 cm$

Solution

Q.
Figure 1 shows the configuration of main scale and Vernier scale before measurement. Fig. 2 shows the configuration corresponding to the measurement of diameter D of a tube. The measured value of D is : [2025]

1 0.12 cm

2 0.11 cm

3 0.13 cm

4 0.14 cm

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