FeO 4 2 - + 2.2V Fe 3 + + 0.70V Fe 2 + - 0.45V Fe 0 E FeO 4 2 - / Fe 2 + is x × 10 - 3 V . The value of x is _______. [2023]

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Solution

Q.
${FeO}_{4}^{2 -} \overset{+ 2.2 V}{\to} {Fe}^{3 +} \overset{+ 0.70 V}{\to} {Fe}^{2 +} \overset{- 0.45 V}{\to} {Fe}^{0}$

$E_{{FeO}_{4}^{2 -} / {Fe}^{2 +}}^{θ}$ is $x \times 10^{- 3} V .$ The value of $x$ is _______. [2023]

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