Expression for an electric field is given by $\vec{E} = 4000 x^{2} \hat{i} V/m .$ The electric flux through the cube of side 20 cm when placed in the electric field (as shown in the figure) is ________ V cm. [2023]

Question

Smart Achievers · Accepted Answer

(640)

$Flux = \vec{E} \cdot \vec{A} = 4000 {(0.2)}^{2} \frac{V}{m} \cdot {(0.2)}^{2} m^{2}$

$= 4000 \times 16 \times 10^{- 4} V m = 640 Vcm$

Solution

Q.
Expression for an electric field is given by $\vec{E} = 4000 x^{2} \hat{i} V/m .$ The electric flux through the cube of side 20 cm when placed in the electric field (as shown in the figure) is ________ V cm. [2023]

Ans.
(640)

$Flux = \vec{E} \cdot \vec{A} = 4000 {(0.2)}^{2} \frac{V}{m} \cdot {(0.2)}^{2} m^{2}$

$= 4000 \times 16 \times 10^{- 4} V m = 640 Vcm$

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Solution

Q. Expression for an electric field is given by E→=4000x2i^ V/m. The electric flux through the cube of side 20 cm when placed in the electric field (as shown in the figure) is ________ V cm. [2023]

Ans. (640) Flux=E→·A→=4000(0.2)2Vm·(0.2)2 m2 =4000×16×10-4 V m=640 Vcm

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Q.
Expression for an electric field is given by $\vec{E} = 4000 x^{2} \hat{i} V/m .$ The electric flux through the cube of side 20 cm when placed in the electric field (as shown in the figure) is ________ V cm. [2023]

Ans.
(640)

$Flux = \vec{E} \cdot \vec{A} = 4000 {(0.2)}^{2} \frac{V}{m} \cdot {(0.2)}^{2} m^{2}$

$= 4000 \times 16 \times 10^{- 4} V m = 640 Vcm$