Electrons with de-Broglie wavelength fall on the target in an X-ray tube

Question

Electrons with de-Broglie wavelength $λ$ fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-rays is

Smart Achievers · Accepted Answer

(1)

$p = \frac{h}{λ}$

$K.E. = \frac{p^{2}}{2 m} = \frac{h^{2}}{2 m λ^{2}}$

$\frac{h^{2}}{2 m λ^{2}} = \frac{h c}{λ_{0}}$

$λ_{0} = \frac{2 m c λ^{2}}{h}$

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