Dimension of should be equal to [2023]

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Solution

Q.
Dimension of $\frac{1}{μ_{0} ε_{0}}$ should be equal to [2023]

1 $\frac{L}{T}$

2 $\frac{L^{2}}{T^{2}}$

3 $\frac{T}{L}$

4 $\frac{T^{2}}{L^{2}}$

Ans.
(2)

$\frac{1}{μ_{0} ε_{0}} = c^{2} \Rightarrow [\frac{1}{μ_{0} ε_{0}}] = [c^{2}] = [L^{2} T^{- 2}]$

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