current I is situated near a long straight wir

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Q.
A rectangular loop carrying a current I is situated near a long straight wire such that the wire is parallel to one of the sides of the loop and is in plane of the loop. If steady current I is created in wire as shown in figure below, then the loop:

1 Rotate about an axis parallel to the wire

2 Move towards the wire

3 Move away from the wire or towards right

4 Remains stationary

Ans.
(2)

$F o r c e F = \frac{μ_{0} 2 i_{1} i_{2}}{4 π r} ∴ F \propto \frac{1}{r} A s r_{1} < r_{2} ∴ F_{1} > F_{2} ∴ F_{net} = F_{1} - F_{2}$

(Directed towards the wire)

Solution

Q.
A rectangular loop carrying a current I is situated near a long straight wire such that the wire is parallel to one of the sides of the loop and is in plane of the loop. If steady current I is created in wire as shown in figure below, then the loop:

1 Rotate about an axis parallel to the wire

2 Move towards the wire

3 Move away from the wire or towards right

4 Remains stationary

Ans.
(2)

$F o r c e F = \frac{μ_{0} 2 i_{1} i_{2}}{4 π r} ∴ F \propto \frac{1}{r} A s r_{1} < r_{2} ∴ F_{1} > F_{2} ∴ F_{net} = F_{1} - F_{2}$

(Directed towards the wire)

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Solution

Q. A rectangular loop carrying a current I is situated near a long straight wire such that the wire is parallel to one of the sides of the loop and is in plane of the loop. If steady current I is created in wire as shown in figure below, then the loop:

1 Rotate about an axis parallel to the wire

2 Move towards the wire

3 Move away from the wire or towards right

4 Remains stationary

Ans. (2) Force F=μ02i1i24πr∴ F∝1rAs r1<r2∴ F1>F2∴ Fnet=F1-F2 (Directed towards the wire)

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Q.
A rectangular loop carrying a current I is situated near a long straight wire such that the wire is parallel to one of the sides of the loop and is in plane of the loop. If steady current I is created in wire as shown in figure below, then the loop:

Ans.
(2)

$F o r c e F = \frac{μ_{0} 2 i_{1} i_{2}}{4 π r} ∴ F \propto \frac{1}{r} A s r_{1} < r_{2} ∴ F_{1} > F_{2} ∴ F_{net} = F_{1} - F_{2}$

(Directed towards the wire)