cos(α-β)=1 and cos(α+β)=1e, where α,β∈[-π,π]. Pairs of α,β which satisfy both the equations is/are [2005]
(4)
Given: cos(α-β)=1 and cos(α+β)=1e, where α,β∈[-π,π]
Now, cos(α-β)=1⇒α-β=0⇒α=β
and cos(α+β)=1e⇒cos2α=1e
∵ 0<1e<1
Now 2α∈[-2π,2π]
⇒There will be two values of 2α in [-2π,0] satisfying cos2α=1e and two values in [0,2π].
⇒There will be four values of α in [-π,π] and correspondingly four values of β. Hence there are four sets of (α,β).