Q.

cos(α-β)=1 and  cos(α+β)=1e, where α,β[-π,π]. Pairs of α,β which satisfy both the equations is/are        [2005]

1 0  
2 1  
3 2  
4 4  

Ans.

(4)

Given: cos(α-β)=1 and cos(α+β)=1e,  where α,β[-π,π]

Now, cos(α-β)=1α-β=0α=β

and cos(α+β)=1ecos2α=1e

  0<1e<1

Now 2α[-2π,2π]

There will be two values of 2α in [-2π,0] satisfying cos2α=1e and two values in [0,2π].

There will be four values of α in [-π,π] and correspondingly four values of β. Hence there are four sets of (α,β).