Correct order of stability for the following is CH 2 = CH - , CH 3 - CH 2 - , CH ? C - [2026]

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Solution

Q.
Correct order of stability for the following is
${CH}_{2} = {CH}^{-}, {CH}_{3} - {CH}_{2}^{-}, CH \equiv C^{-}$ [2026]

1 $CH \equiv C^{-} > {CH}_{2} = {CH}^{-} > {CH}_{3} - C {H_{2}}^{-}$

2 $CH \equiv C^{-} > {CH}_{3} - {CH}_{2}^{-} > {CH}_{2} = {CH}^{-}$

3 ${CH}_{2} = {CH}^{-} > CH \equiv C^{-} > {CH}_{3} - {CH}_{2}^{-}$

4 ${CH}_{3} - C {H_{2}}^{-} > {CH}_{2} = {CH}^{-} > CH \equiv C^{-}$

Ans.
(1)

${CH}_{2} = {CH}^{-} {CH}_{3} > {CH}_{2}^{-} CH \equiv C^{-}$

$Stability \propto % S$

$Order of stability$

$CH \equiv C^{-} > {CH}_{2} = {CH}^{-} > {CH}_{3} - {CH}_{2}^{-}$

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