Considering only the principal values of the inverse trigonometric functions, the value of
32cos-122+π2+14sin-1(22π2+π2)+tan-1(2π) is ________. [2022]
(2.36)
[Let, cos-122+π2=t=tan-1(π2)]
{Similarly for sin-1(22π2+π2)}
Now, we have
32tan-1(π2)+14tan-1(22ππ2-2)+tan-1(2π)
=π2+12tan-1(π2)-14tan-1(22π2-π2)
=π2+12tan-1(π2)-14tan-1(2(π2)1-(π2)2)
=π2+12tan-1(π2)-14(-π+2tan-1(π2))
=π2+π4=3π4=2.36