Q.

Consider the following radioactive decay process:

A84218→αA1→β-A2→γA3→αA4→β+A5→γA6

The mass number and the atomic number of A6 are given by:              [2023]

1 211 and 80  
2 210 and 80  
3 210 and 82  
4 210 and 84  

Ans.

(2)

A84218 →αA182214 →β-A283214 →γ A383214

A383214 →α A481214 →β+ A580210 →γ A680210