Consider the expansion of one mole of an ideal gas from an initial state to a final state, with representing the entropy change in the process. The correct statement is:

Question

Consider the expansion of one mole of an ideal gas from an initial state to a final state, with $ΔS$ representing the entropy change in the process. The correct statement is:

Smart Achievers · Accepted Answer

(4)

$For isothermal, Δ S_{sys} = n R l n (\frac{V_{f}}{V_{i}})$

Solution

Q.
Consider the expansion of one mole of an ideal gas from an initial state to a final state, with $ΔS$ representing the entropy change in the process. The correct statement is:

1 If the process is carried out reversibly, the value of $ΔS$ will be higher in comparison to its irreversible counterpart.

2 If the process is adiabatic, the value of $ΔS$ is always zero, irrespective of whether the process is carried out reversibly or irreversibly.

3 If the process is isothermal, there will not be any heat exchange with the surrounding since the temperatures of the system and the surrounding are equal.

4 If the process is isothermal and the final volume is double of the initial volume, the value of $ΔS$ will be independent of the temperature.

Ans.
(4)

$For isothermal, Δ S_{sys} = n R l n (\frac{V_{f}}{V_{i}})$

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Solution

Q. Consider the expansion of one mole of an ideal gas from an initial state to a final state, with ΔS representing the entropy change in the process. The correct statement is:

1 If the process is carried out reversibly, the value of ΔS will be higher in comparison to its irreversible counterpart.

2 If the process is adiabatic, the value of ΔS is always zero, irrespective of whether the process is carried out reversibly or irreversibly.