Q.

Consider a uniform spherical charge distribution of radius R1 centred at the origin O. In this distribution, a spherical cavity of radius R2, centred at P with distance OP=a=R1-R2 (see figure), is made. If the electric field inside the cavity at position r→ is E→(r→), then the correct statement(s) is (are)          [2015]

1 E→ is uniform, its magnitude is independent of R2, but its direction depends on r→.  
2 E→ is uniform, its magnitude depends on R2, and its direction depends on r→.  
3 E→ is uniform, its magnitude is independent of a, but its direction depends on a→.  
4 E→ is uniform and both its magnitude and direction depend on a→.  

Ans.

(4)

Let us consider a point M inside the cavity where the electric field has to be calculated. Assume the cavity contains a similar charge distribution of positive and negative charge as the rest of the sphere. Electric field at M due to uniformly distributed charge of the whole sphere of radius R1

E→1=ρ3εr→

Electric field at M due to the negative charge distribution in the cavity

E→2=ρ3εMP→

∴  The total electric field at M inside the cavity

E→=E→1+E→2=ρ3εr→+ρ3εMP→

∴  E→=ρ3εr→+ρ3ε(a→-r→)           [∵ r→+MP→=a→]

∴  E→=ρ3εa→

Hence inside the cavity E→ is uniform and both its magnitude and direction depend on a→.