Q.

Consider a system of three charges q/3, q/3 and -2q/3 placed at points A, B and C, respectively, as shown in the figure. Take O to be the centre of the circle of radius R and angle CAB=60°.                        [2008]

1 The electric field at point O is q8πε0R2 directed along the negative x-axis.  
2 The potential energy of the system is zero.  
3 The magnitude of the force between the charges at C and B is q254πε0R2  
4 The potential at point O is q12πε0R  

Ans.

(3)

(1) The electric field due to charge q3 at A and charge q3 at B at O will get cancelled. The electric field at O due to charge (-2q3) is

E=14πε02q/3R2=q6πε0R2.

In ABCACAB=sin30°

AC=AB2=R

Also, BCAB=sin60°BC=3AB2=3R

(2) Potential energy of the system K[(q/3)(q/3)2R]+K[(q/3)(-2q/3)R]+K[(q/3)(-2q/3)3R]

      =kq29R[12-2-23]0

(3) Magnitude of force between B and C   F=14πε0(2q/3)(q/3)(3R)2=q254πε0R2

(4) Potential VO=K[+q/3R]+K[+q/3R]+K[-2q/3R]=0