Cobalt(III) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at ? [2015]

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Q.
Cobalt(III) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at $25^{o} C$ [2015]

1 ${CoCl}_{3} \cdot 5 {NH}_{3}$

2 ${CoCl}_{3} \cdot 6 {NH}_{3}$

3 ${CoCl}_{3} \cdot 3 {NH}_{3}$

4 ${CoCl}_{3} \cdot 4 {NH}_{3}$

Ans.
(3)

For octahedral complexes, coordination number is 6. Hence, ${CoCl}_{3} \cdot 3 {NH}_{3}$ , i.e., $[{Co(NH}_{3})_{3} {Cl}_{3}]$ will not ionise and will not give test for ${Cl}^{-}$ ion with silver nitrate.

Solution

Q.
Cobalt(III) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at $25^{o} C$ [2015]

1 ${CoCl}_{3} \cdot 5 {NH}_{3}$

2 ${CoCl}_{3} \cdot 6 {NH}_{3}$

3 ${CoCl}_{3} \cdot 3 {NH}_{3}$

4 ${CoCl}_{3} \cdot 4 {NH}_{3}$

Ans.
(3)

For octahedral complexes, coordination number is 6. Hence, ${CoCl}_{3} \cdot 3 {NH}_{3}$ , i.e., $[{Co(NH}_{3})_{3} {Cl}_{3}]$ will not ionise and will not give test for ${Cl}^{-}$ ion with silver nitrate.

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Solution

Q. Cobalt(III) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at 25oC [2015]

1 CoCl3·5NH3

2 CoCl3·6NH3

3 CoCl3·3NH3

4 CoCl3·4NH3

Ans. (3) For octahedral complexes, coordination number is 6. Hence, CoCl3·3NH3, i.e., [Co(NH3)3Cl3] will not ionise and will not give test for Cl- ion with silver nitrate.

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Q.
Cobalt(III) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at $25^{o} C$ [2015]

1 ${CoCl}_{3} \cdot 5 {NH}_{3}$

2 ${CoCl}_{3} \cdot 6 {NH}_{3}$

3 ${CoCl}_{3} \cdot 3 {NH}_{3}$

4 ${CoCl}_{3} \cdot 4 {NH}_{3}$

Ans.
(3)

For octahedral complexes, coordination number is 6. Hence, ${CoCl}_{3} \cdot 3 {NH}_{3}$ , i.e., $[{Co(NH}_{3})_{3} {Cl}_{3}]$ will not ionise and will not give test for ${Cl}^{-}$ ion with silver nitrate.