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Solution


Q.

Read the passage given below and answer the following questions from (i) to (v).

The electrical energy consumed by an electrical appliance is given by the product of its power rating and the duration for which it is used. SI unit of electrical energy is the joule. Where a large quantity of energy is involved, using a joule is not convenient as a unit. So, for commercial purposes, bigger units of electrical energy are involved. 1 space k i l o w a t t minus h o u r space equals space space 3.6 space cross times space 10 to the power of 6 space space j o u l e s of electrical energy.

 

(iv) Choose the correct statement:
1 1 watt-hour = 3600 J  
2 1 kWh =  36 × 106 J  
3 Energy in kWh = power in W (watt) × time in hour (h)  
4 Energy in kWh = V × I × T × 1000  

Ans.

(1)